Mathematics
Mathematics, 27.01.2021 22:20, DragonLovely

PLEASE HELP Quadrilateral PQRS is located at P (βˆ’4, 1), Q (βˆ’2, 3), R (1, 1), and S (βˆ’2, βˆ’2). Russell and Jamie have both classified PQRS differently. Examine their proofs. Who is correct?

Russell Jamie
PQRS is a parallelogram because both pairs of opposite sides are parallel
Segment PQ
P (βˆ’4, 1) and Q (βˆ’2, 3)
m equals 3 minus 1 over negative 2 plus 4 equals 2 over 2 equals 1

Segment SR
S (βˆ’2, βˆ’2) and R (1, 1)
m equals 1 plus 2 over 1 plus 2 equals 3 over 3 equals 1

Segment PS
P (βˆ’4, 1) and S (βˆ’2, βˆ’2)
m equals negative 2 minus 1 over negative 2 plus 4 equals negative 3 over 2

Segment QR
Q (βˆ’2, 3) and R (1, 1)
m equals 1 minus 3 over 1 plus 2 equals negative 2 over 3

Segments PQ and SR are parallel, and segments PS and QR are parallel. PQRS is a parallelogram because both pairs of opposite sides are congruent

Segment PQ
P (βˆ’4, 1) and Q (βˆ’2, 3)
d equals the square root of the quantity negative 2 plus 4 all squared plus 3 minus 1 all squared equals the square root of the quantity 4 plus 4 equals the square root of 8 equals 2 times the square root of 2

Segment SR
S (βˆ’2, βˆ’2) and R (1, 1)
d equals the square root of the quantity 1 plus 2 all squared plus 1 plus 2 all squared equals the square root of the quantity 9 plus 9 equals the square root of 18 equals 3 times the square root of 2

Segment PS
P (βˆ’4, 1) and S (βˆ’2, βˆ’2)
d equals the square root of the quantity negative 2 plus 4 all squared plus negative 2 minus 1 all squared equals the square root of the quantity 4 plus 9 equals the square root of 13

Segment QR
Q (βˆ’2, 3) and R (1, 1)
d equals the square root of the quantity 1 plus 2 all squared plus 1 minus 3 all squared equals the square root of the quantity 9 plus 4 equals the square root of 13

Segments PQ and SR are congruent, and segments PS and QR are congruent.
Russell
Jamie
Both
Neither

answer
Answers: 2

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PLEASE HELP Quadrilateral PQRS is located at P (βˆ’4, 1), Q (βˆ’2, 3), R (1, 1), and S (βˆ’2, βˆ’2). Russel...

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