Estimate the difference. Round each number to the nearest whole number, then subtract. 6 3/4 - 2 1/2

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

What is the maximum of the sinusoidal function

Arectangle has a length of 6cm by 8cm what is the length of a diagonal of the rectangle