PLEASE HELP...The average amateur golfer can hit a ball with an initial upward velocity of 28.3 meters per second. The height can be modeled by the equation h = -4.9t^2 +28.3t, where h is the height of the ball in meters, after t seconds Questions: At what height is the ball hit? When is the ball at its maximum height?What is the maximum height of the ball?

b 1: 45 am

step-by-step explanation:

its that because if it was in the pm it would be 1345

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )