The average amateur golfer can hit a ball with an initial upward velocity of 28.3 meters per second. The height can be modeled by the equation h = -4.9t^2 +28.3t, where h is the height of the ball in meters, after t seconds Questions: At what height is the ball hit? When is the ball at its maximum height?What is the maximum height of the ball?

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!