Jason has 150 cents nickels and quarters. if the number of nickels he has is 5 less than the twice the number of quarters, how many nickels does he have?

Let's set up some simultaneous equations. Let the number of nickels be n, and the number of quarters be q. Now I'm from England so I had to look up the value of a nickel (I could guess the quarter though to be 25c), but apparently it's 5c

Okay we know that the total value of the coins is 150. This gives:

25q + 5n = 150

Rearranging to make n the subject:

n = 30 - 5q

Next, we use the second statement:

n = 2q - 5

Substituting this into the first equation:

2q - 5 = 30 - 5q
7q = 35
q = 5

Putting this value for q into the first equation:

n = 30 - 5(5) = 5

Hence he has 5 of each coin. I hope this helps :)

Here are the answers to the ones that i could see.