Someone PLS HELP BRAINLIESTThe length of a rectangle is 3m more than twice the width, and the area of the rectangle is 35m^2 . Find the dimensions of the rectangle. Length:
Width:

Let width of the rectangle be x.

Therefore ,Length= 3 + 2x

Area= 35

(3+2x)* x =35

3x + 2x^2 - 35 = 0

(2x-7)(x+5)

Therefore x=3.5

Length is 10 and Width is 3.5

Area = length × width

90 = (3+2w) × w

w(2w + 3) = 90

2w² +3w = 90

2(w² +3/2w) = 90

Divide both sides by 2

2(w² +3/2w)/2 = 90/2

w² + 3/2w = 45

w² + 3/2w + (3/2•2)² = 45 + (3/2•2)²

w² + 3/2w + (3/4)² = 45 + (3/4)²

w² + 3/2w + 9/16 = 45 + 9/16

(w + 3/4)² = 729/16

Take the square root of both sides

√(w + 3/4)² = √729/16

w + 3/4 = 27/4

w + 3/4 -3/4 = ±27/4 - 3/4

w = 27/4 - 3/4 w = -27/4 - 3/4

w = 6m w = -7.5m

Area = length × width

90 = l × 6m

when x = 6m when x = -7.5 m

l = 90 m²/6m l = 90 m²/-7.5m

l = 15 m l = -12m

We cannot have negative dimension so

A = 90m²

l = 15m

w = 6m

Step-by-step explanation:

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step-by-step explanation: