Select the TWO systems of equations that have exactly one solution A. y= 3x + 1
y= -3x + 7

B. y= 3x + 1
y = x + 1

C. y= 3x + 1
y = 3x + 7

D. x + y = 10
2x + 2y = 20

E. x + y = 10
x + y = 12

D

Step-by-step explanation:

for D

let (x,y) = (5,5)

5+5=10

5+5=102×5+2×5=20

let (x,y) = (6,4)

6+4=10

6+4=102×6+2×4=20

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560