The velocity of the water that flows from an opening at the base of a tank depends on the height of water above the opening. The function v(x) = √ 2gx models the velocity, v(x), in feet per second where g, the acceleration due to gravity, is about 32 feet per second squared and x is the height in feet of the water. What is the height, in feet, of the water in the tank when the velocity of the flow is 40 feet per second?

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

here is a big fat

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14