What is the domain and range of the inverse of: f (x)= (x + 2)² - 1

The inverse of this function is a parabola that has been rotated 90 degrees clockwise, with it's vertex at point 1, 0.

So it's domain is x ≥ 1

And it's range is y ≥ -2

Step-by-step explanation:

Given:

f(x) = (x + 2)² - 1

First we find the inverse:

x = (f(x) + 2)² - 1

x - 1 = (f(x) + 2)²

√(x - 1) = f(x) + 2

f(x) =  -2 ± √(x - 1)

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5