A model rocket is launched upward with an initial velocity of 230 feet per second. The height, in feet, of the rockett seconds after the launch is given by h - -16+2300. How many seconds after the launch will the rocket be 330 feet above the ground? Round to the nearest tenth of a second.

given : the shape of his satellite can be modeled by   where x and y are modeled in inches.

now,the given equation   is a equation of parabola.

here, coefficient of x is positive, hence the parabola opens rightwards.

on comparing this equation with standard equation , we get

in standard equation, coordinates of focus=(0,m)

thus for given equation coordinates of focus=(0,1.5)

step-by-step explanation: