Find the area of the isosceles triangle formed by points of intersection of the parabolas y=-x2+9 and y=2x2+3 and the origin.

10

Step-by-step explanation:

*I’m assuming that you meant y = 2x^2-3 because that is what my RSM problem was and it was exactly the same problem other than that.* First you want to find the points of intersection of the two parabolas. You can choose to graph them or do any other method. Anyways, the points of intersection are: (2,5) and (-2,5). You now want to add (0,0). So obviously (2,5) to (-2,5) is the base and it is 4 units. The height is 0 to 5 which is 5 units. Do (4*5)/2 and you get 10. Hope this helped you with your RSM and let me know if I assumed correctly.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: