Helpp ill mark u as brain list

19.7

Step-by-step explanation:

We need to find the hypotenuse of the blue triangle, as stated in the hint. We know the sides of the base measure 8 x 15 respectively so let's use Pythagorean Theorem;

8^2 + 15^2 = (hyp.)^2,

hyp = √8^2 + 15^2 = √64 + 225 = √289 = 17

Now the height of the yellow triangle is 10 inches. The hypotenuse of the blue triangle is now the base of the yellow triangle. The dimensions are 10 x 17 respectively so we can determine it's hypotenuse;

hyp (yellow triangle) = √17^2 + 10^2

                                   = √289 + 100

                                   = √389 ≈ 19.7 in.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: