Find the least counting number which when divided by 5 gives the remainder of 1 and when divided by 12 gives us the remainder of 3

51

Step-by-step explanation:

Let x be the number

When x divided by 5 then it gives remainder 1 and when divided by 12 gives remainder 3.

We have to  the value of x.

Using Euclid's algorithm

Where

...(1)

When q=10 and p=4

Then,

q=10 and p=4 satisfied the equation (1)

Substitute q=10

Hence,51 is  the least counting number  which when divided by 5 gives the remainder of 1 and when divided by 12 gives us the remainder of 3.

ummm seems that u didnt post the attachement !

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6