I'll legit cry if you can show me a step by step on how to solve this... pls oh my god

x=4

ab=51

ac=51

Step-by-step explanation:

Call the point at the centre of the circle 'X'

1) Draw two lines from X, one joining B and one joining C. Each line is a radius.

2)Draw a line from A to X.

3) We now have two triangles: ΔABX and ΔACX.

4) We know that these triangles are congruent as we can say with certain they share two of the same side lengths (BX=CX because they're both the radius, and AX is common to both triangles).

4)Knowing that they're congruent, we can say that AB=AC:

AB=AC

14x-5=3+12x

14x-12x=3+5

2x = 8

x = 4

Therefore AB=14(4)-5=51

AC=3+12(4)=51

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option