The populations and land areas of four cities in Texas are shown. Which statements are true? Check all that apply. The population density for City B can be found using the ratio 48,592 : 26. The population density for City D can be found using the ratio 258 : 196,429. City A has the greatest population density of the four cities. The population density of City B is greater than that of City C. City D has the lowest population density of the four cities.

The population density for city b would be 48,592 ÷ 26  

The population density for city b is more than the city c

And, the city d contains the lowest population density

Step-by-step explanation:

The computation is given below:

As we know that

Population density = Population ÷ Area

So

For city A = 2,195,914 ÷ 1,553 = 1413.98

For city B = 48,592 ÷ 26 = 1868.15

For city C = 1,257,676 ÷ 999 = 1258.93.

For city D = 196,429 ÷ 258 = 761.35.

The following are the true statements:

The population density for city b would be 48,592 ÷ 26  

The population density for city b is more than the city c

And, the city d contains the lowest population density

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide