Side length z =

angle d =

a) side length z = 19.965 ≅ 20m

b) angle 'd' = 53.13°

Step-by-step explanation:

Step(i):-

Given that ∠HIG is a right angle triangle

Given∠I = 53°

By using the sine function

 z = 25 × sin53° = 25×0.798635

z = 19.965 ≅20 m

Step(ii):-

⇒    

⇒   d = 53.13°

Final -

a) side length z = 19.965 ≅ 20m

b) angle 'd' = 53.13°

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1