How much energy is absorbed by 250.0 g of water when its temperature rises from 25.0 ºC to 88.5 ºC? Specific heat capacity of water is 4.184 J/gºC.

.

(4.18 J/g°C) x (100.0 mL x 1.000 g/mL) x (37 - 4.0)°C = 13794 J = 13 kJ

2.  

(455 J) / (25.0 g) / (155 - 25)°C = 0.140 J/g°C

3.  

(4.184 J/g°C) x (20.0 g) x (303.0 - 283.0)°C = 1674 J

5.  

(0.129 J/g °C) x (85.0 g) x (200.0 - 10.0)°C = 2083 J

Step-by-step explanation:

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the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

the answer is two. hope this !