What is an equation of the line that passes through the points (0, -2) and (-4, 4)?

y=-3/2x-2

Step-by-step explanation:

first, we must calculate the slope (m) using the equation (y2-y1)/(x2-x1)

here are the given points: (0,-2) and (-4,4)

we can label the points:

x1=0

y1=-2

x2=-4

y2=4

now substitute into the equation:

m=(4--2)/(-4-0)

m=(4+2)/-4

m=6/-4

m=3/-2

m=-3/2

the slope of the line is -3/2

now use the point-slope form, which is y-y1=m(x-x1)

substitute the given numbers into the equation

y--2=-3/2(x-0)

do distributive prop.

y+2=-3/2x

subtract 2 from both sides

y=-3/2x-2

y=mx+

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times