A farmhouse shelters 14 animals. Some are pigs, and some are chickens. Altogether there
are 44 legs between the animals. Let p
represent the number of pigs and c represent
the number of chickens.

9514 1404 393

8 pigs6 chickens

Step-by-step explanation:

Maybe you want to know the number of each kind of animal.

__

We can write two equations in the two unknowns.

  p + c = 14 . . . . . . number of animals

  4p +2c = 44 . . .  number of legs

Dividing the second equation by 2, it becomes ...

  2p +c = 22

Then subtracting the first equation gives ...

  (2p +c) -(p +c) = (22) -(14)

  p = 8

  8 +c = 14

  c = 6

The farmhouse shelters 8 pigs and 6 chickens.

Neither is the answer

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

ac ≅ ab (given)< cax ≅ < bax   (given)ax ≅ ax (common side)

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)