What are the quotient and remainder of (3x* + 2x2 - 6x + 1) = (x+1)? a. 3x2 – 3x2 + 5x-11; 12
C. 3x2 – 3x2 + 5x-11; -12
b. 3x3 - 2x + 5x-11; 12
d. 3x3 - 3x2 + 5x+11 -12
C.
Please select the best answer from the choices provided
A
B

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

c

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

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step-by-step explanation: