Jordan is paying off a car loan. The function that models how much he has left to pay on his loan, P, is P(m)=6000−300m, where m is the number of months since Jordan took out the loan. What was the original amount of the loan? A.) $18,000
B.) $6,000
C.) $20
D.) $300

B.) $6,000

Step-by-step explanation:

The equation shows how much Jordan has to pay per month until he is finished paying the loan.

This is a linear equation in the form: y = mx + c

y is the amount left to be paid

m is the change per month which means it is the amount paid per month

x is the independent variable that is changed which means it is the no. of months

c is a constant figure which in this case would be the amount borrowed.

With c being the amount borrowed as it is the constant in the equation, c in the equation must be 6,000 as this is the only constant.

The original amount of loan must therefore be:

= $6,000

answer: idk

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.