The failure of a circuit board interrupts work that utilizes a computing system, until a new board is delivered. The delivery time, Y, is uniformly distributed on the interval two to six days. The cost of a board failure and interruption includes the fixed cost c0 of a new board and a cost that increases proportionally to Y2. If C is the cost incurred, C = c0 + c1Y2. A) Find the probability that the delivery time exceeds two days.
B) In terms of c0 and c1, find the expected cost associated with a single failed circuit board.

a) 1  ( 100% )

b)   Co + 46/3 C1

Step-by-step explanation:

Delivery time = Y

Interval = 2 to 6 days

cost incurred ( C ) = Co + C1 Y^2

a) determine the probability that the delivery time exceeds two days

since the delivery time is uniformly distributed on the interval 2 to 6 days the probability of having a delivery time > 2 days will be = 1

b) Determine the expected cost associated with a single failed circuit board

E ( Y^2 ) = 46/3

hence the cost associated with a single failed circuit board =

E ( C ) = Co + 46/3 C1

attached below is a detailed solution

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: