Find the missing lengths of the sides.
12V2 ft
45°
a
b

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

x^2 + 10x + 38 + 161/x-4

to find this, you'll need to synthetically divide using synthetic division.

here's how you would set it up:

4 is what you're dividing by (set x -4 = 0)

the numbers you are 'dividing' by are 1, 6, -2, and 9 or the coefficients of the terms listed above.

bring the first term down (1), multiply that by 4 before raising it to the next term to add (6). repeat this process as so:

6 + 4 = 10; 10 x 4 = 40; 40 - 2 = 38 x 4 = 152 + 9 = 161

161 is over x-4 as there are now two constants and you cannot combine them.

also, i'm not sure if it was -9 or +9, so i assumed.

hope this !