What is an equation of the line that passes through the points (5,2) and (-5,6)? Put your answer in fully reduced form.

y = -2/5x + 4

Steps:

First find the slope of the equation y=mx+b.

slope equation (m=y2-y1/x2-x1)

Then plug in your coordinates, which the first set is (5,2) and the second set if (-5,6). m = 6 - 2/ -5 - 5

Which your answer will be 4/-10, simplify it by dividing both by 2 to get -2/5 for your slope.

Next, find your y-intercept (b).

substitute the first set of coordinates into the equation y=mx+b

Substitute: 2 = -2/5 (5) +b

Then multiply -2/5 with 5 to get (-2). Your equation should now reduce to be

2 = -2 +b

Do inverse operations on both sides by adding 2 to each side (the 2 side and the -2+b side).

This gets rid of the -2 and since we added 2 to both sides, your final equation should look like 4 = b for your y-intercept.

Plug in everything to get y = -2/5x + 4