△XYZ is translated up 3 units to form the image ∆X′Y′Z′. What are the coordinates of the vertices of ∆X′Y′Z′ ?

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The coordinates of the vertices of ∆X′Y′Z′:

Step-by-step explanation:

Given the triangle △XYZ with the vertices

It is stated that △XYZ is translated up 3 units to form the image ∆X′Y′Z′.

Translating 3 units UP means we have to add 3 units to all the y-coordinates of the coordinates of the vertices X, Y, and Z to generate the image ∆X′Y′Z′.

Thus,

THE RULE OF TRANSLATING 3 UNITS UP:

P(x, y) → P'(x, y+3)

Therefore, the coordinates of the vertices of ∆X′Y′Z′ will be:

X(-4, 6) → X'(-4, 6+3) → X'(-4, 9)

Y(1, 6) → Y'(1, 6+3) → Y'(1, 9)

Z(1, 1) → Z'(1, 1+3) → Z'(1, 4)

Thus, the coordinates of the vertices of ∆X′Y′Z′:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204