(5, 2);
2x +y= 12
—3y - х = -11
I’m confused help !

so (5;2) belongs to these equaliations

Step-by-step explanation:

(5;2) is the same as (x;y)

so u just plug in your numbers

—3y - х = -11

-3*2-5=-11

-6-5=-11

-11=-11

2x +y= 12

2*5+2=12

12=12

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204