During a competition, an archer fires an arrow at a target on a hill. The arrow reaches a maximum
height of 127 feet 2.75 seconds after it was fired.
The arrow hits the target 5 seconds after the archer
releases it. If the arrow is released from a height of
6 feet, how far above the ground on which the
archer is standing is the target? Assume the
relationship between time and height is quadratic.

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb

113.1

step-by-step explanation:

v=4

3πr3=4

3·π·33≈113.09734