Rhombus PQRS with vertices P(-8, 6), Q(-4, 8), R(0, 6), and S(-4, 4) REFLECTED over the line y = 2.

P'(-8, -2), Q'(-4, -4), R'(0, -2) and  S'(-4, 0)

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.

Reflection is the flipping of a point about an axis.

Given the Rhombus PQRS with vertices P(-8, 6), Q(-4, 8), R(0, 6), and S(-4, 4), if the rhombus is reflected over the y = 2 line the new point is:

For P(-8, 6): The point P has a y coordinate 4 units above the y = 2 line. Hence if it is reflected over the line y = 2, the new point would have a y coordinate 4 units below the y = 2 line which is P'(-8, -2)

For Q(-4, 8): The point Q has a y coordinate 6 units above the y = 2 line. Hence if it is reflected over the line y = 2, the new point would have a y coordinate 6 units below the y = 2 line which is Q'(-4, -4)

For R(0, 6): The point R has a y coordinate 4 units above the y = 2 line. Hence if it is reflected over the line y = 2, the new point would have a y coordinate 4 units below the y = 2 line which is R'(0, -2)

For S(-4, 4): The point S has a y coordinate 2 units above the y = 2 line. Hence if it is reflected over the line y = 2, the new point would have a y coordinate 2 units below the y = 2 line which is S'(-4, 0)

Therefore the reflected rhombus is at P'(-8, -2), Q'(-4, -4), R'(0, -2) and  S'(-4, 0)

it is b)

hope this : )

step-by-step explanation:

529 and 531

step-by-step explanation: