N a box of 12 tape measures, there is one that does not work. Employees take a tape measure as needed. The tape measures are not returned, once taken. You are the 8th employee to take a tape measure. Is this a binomial experiment? a. Yes, the probability of success is one out of 12 with 8 selected.
b. No, the probability of getting the broken tape measure changes as there is no replacement.
c. Yes, you are finding the probability of exactly 5 not being broken.
d. No, binomial does not include systematic selection such as "eighth".

b. No, the probability of getting the broken tape measure changes as there is no replacement.

Step-by-step explanation:

For each tape measure, there are only two possible outcomes. Either it is broken, or it is not, which means that the first condition for the binomial distribution is respected.

However, the tapes are not returned to the box, which means that in each trial, the probabilities of getting the tape with defect changes, which means that the binomial distribution cannot be used. So option b is the correct answer

i could probably can you me with a question of mine?

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v