The equation can be used to find the approach velocity v (in feet per second) of a pole-vaulter and where h represents the height a pole-vaulter can reach. Erwin and Elmer are pole-vaulters. In one of the events they participated, Erwin’s approach velocity was 40 feet per second while Elmer’s approach velocity was 35 per second. Who reached greater height? Justify your answer.

Missing part of question:

A pole-vaulter’s approach velocity v (in feet per second) and height reached h (in feet) are related by the following equation.

v=8√h

Erwin

Step-by-step explanation:

The equation is

v=8√h

If velocity is 40 feet per second,

40=8√h

√h=40/8

h=√5

height =2.2360ft

If velocity = 35 feet per second,

v=8√h

35=8√h

√h=35/8

√h= 4.375

height =2.09ft

Therefore Erwin reached greater height =2.2360ft

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

2nd one in the first row is correct