a group buys 6 hot dogs and 3 hamburgers for a total of $27.75. the hamburgers cost $1.75 more than a hot dog. what is he cost of the hamburger

Cost of one hamburger = $4.25

Step-by-step explanation:

Let,

Cost of one hot dog = x

Cost of one hamburger = y

According to given statement;

6x + 3y = 27.75      Eqn 1

y = x + 1.75             Eqn 2

Putting value of y from Eqn 2 in Eqn 1

6x + 3(x+1.75) = 27.75

6x + 3x + 5.25 = 27.75

9x = 27.75 - 5.25

9x = 22.50

Dividing both sides by 9

Putting x=2.50 in Eqn 2

y = 2.50 + 1.75

y = 4.25

Hence,

Cost of one hamburger = $4.25

10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

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