You are running late for work. There are 4 traffic signals on your way to work, and if you make all of them, you will be on time. If you have a 60% chance of making each one, independent of whether or not you made

the previous one, what is the probability that you will make it to work on time?

A. 81/625

B. 64/340

C. 32/125

D. 68/421

E. 25/525

A. 81/625

Step-by-step explanation:

From the question, we are informed that there are 4 traffic signals on ones way to work, and there's a 60% chance of making each one, independent of whether or not the previous one is made.

The probability that one will make it to work on time will be to multiply 60% for the 4 period. This will be:

= 60% × 60% × 60% × 60%

= 60/100 × 60/100 × 60/100 × 60/100

= 3/5 × 3/5 × 3/5 × 3/5

= 81/625

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: