Mathematics, 25.01.2021 08:00, timothyashburn8

What is an equation in point-slope form for the line that contains the points (-1, 4) and (11, -6)?

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answered: pr47723

The equation in point-slope form is $y-4=-\frac{5}{6}(x+1)$

Step-by-step explanation:

Given points are;

(-1, 4) and (11, -6)

We will find the slope of the line through the given points.

Slope = m = $\frac{y_2-y_1}{x_2-x_1}$

m = $\frac{-6-4}{11-(-1)}$

m = $\frac{-10}{12}$

m = $\frac{-5}{6}$

Point slope form of a line is given by;

y-y_1=m(x-x_1)

Putting the point (-1,4) and slope in the equation

$y-4=-\frac{5}{6}(x-(-1))\\y-4 =-\frac{5}{6}(x+1)$

Hence,

The equation in point-slope form is $y-4=-\frac{5}{6}(x+1)$

answered: Guest

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

answered: Guest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is