Finding Distances from the Mean A 2-column table with 5 rows. Column 1 is labeled Robin's Scores with entries 99, 108, 102, 107, 119. Column 2 is labeled Distance from the Mean with entries 8, 1, x, y, z.

The mean of Robin’s scores was 107. Complete the chart to find the absolute distances from the mean for each of Robin’s scores.
ANSWER BELOW HERE
x = 5
y = 0
z = 12

X= 5

Y=0

Z=12

Step-by-step explanation:

Subtract each number from 107

Jus did it as well

1=B 2=B 3=D

Step-by-step explanation:

took the assignment

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

answer: this is not a question

step-by-step explanation: this is a answer