The sum of ages of two ship 12years old .Two years ago, the age of the older ship was three times the age of the newer ship. Find the present age of each ship.

the present age of the old ship is 8 years

The present age of the new ship is 4 years

Step-by-step explanation:

Let the age of the older ship be x

Let the age of newer ship be y

If the sum of ages of two ship 12years old, then;

x + y = 12 1

Two years ago;

Older ship age = x - 2

New ship age = y - 2

If two years ago, the age of the older ship was three times the age of the newer ship, then;

x - 2 = 3(y-2)

x-2 = 3y - 6

x = 3y - 4 2

Substitute equation 2 into 1;

From 1; x+ y = 12

3y-4+y = 12

4y = 12 + 4

4y = 16

y = 4

Since x+y = 12

x = 12-y

x= 12-4

x = 8

Hence the present age of the old ship is 8 years

The present age of the new ship is 4 years

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step-by-step explanation:

just for that im not answering

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb