The 7 a. m. flight from Dallas to Chicago is on time 75% of the time. Fran created this spinner to simulate the scenario. A spinner with 4 equal sections. 3 sections are shaded.

Fran spun the spinner three times to predict whether the flight will be on time or late next Monday, Tuesday, and Wednesday. How should she interpret this outcome of the three spins: shaded-shaded-unshaded?
The flight will be late all three days.
The flight will be on time all three days.
The flight will be late on one of the three days.
The flight will be on time on one of the three days

CORRECT OPTION is (C) The flight will be late on one of the three days.

Step-by-step explanation:

The 7am flight from Dallas to Chicago is on time 75% of the time.

A spinner with four sections was created by Fran to simulate this scenario.

Since the 4 sections were equal, it means each section was 25% of the spinner.

3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.

This coincides with the 75% probability that the flight is on time on a given day.

In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.

Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:

- Shaded   - Shaded   - Unshaded

CORRECT OPTION is (C) The flight will be late on one of the three days.

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d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it