In the fig. AD = DC and AB = BC. Prove that triangle ABD = triangle CDB

Statement                        |   Reason

AD = DC                           |   given

AB = CB                           |    given

BD = DB                           |   reflexive property

ABD = CDB                      |    side-side-side congruency theorem

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse