M IF THE VOLUME OF THE BOX BELOW IS
x3 + 6x2 + 9x + 4
AND THE WIDTH OF THE BOX IS x + 4,
THEN FIND THE LENGTH AND HEIGHT OF
THE BOX

The length of the box is (x + 1)

The height of the box is (x + 1)

Step-by-step explanation:

The given function representing the volume of the box is presented as follows;

V = x³ + 6·x² + 9·x + 4

The function representing the width of the box, W = x + 4

Therefore, we have;

(x³ + 6·x² + 9·x + 4)/(x + 4) = x² + 2·x + 1

x³ + 4·x²

     2·x² + 9·x + 4

     2·x² + 8·x

                  x + 4

Therefore, we have;

(x³ + 6·x² + 9·x + 4) = (x + 4) × (x² + 2·x + 1) = (x + 4) × (x + 1) × (x + 1)

(x³ + 6·x² + 9·x + 4) = (x + 4) × (x + 1) × (x + 1)

The width of the box = (x + 4)

The length of the box = (x + 1)

The height of the box = (x + 1).

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet