Which equations have one solution? Choose all the correct answers. A. 1/3x + 3 = 26 + 6/18x - 23
B. X + 3 + 3x = -3 + 4x + 6
C. 2(1/5 + 1/4x) + 2x = x - 1
D. 4.3x + 2.5 - 2.2x + 2.2 - 2.1x = 0
E. 2(4x + 3) + 2x = 5(2x + 3)
F. 2/5x + 10 + 3/5x = 2x + 5

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x