Isabella is deciding between two parking garages. Garage A charges an initial fee of $4 to park plus $3 per hour. Garage B charges an initial fee of $12 to park plus $2 per
hour. Let A represent the amount Garage A would charge if Isabella parks for t
hours, and let B represent the amount Garage B would charge if Isabella parks for t
hours. Write an equation for each situation, in terms oft, and determine the hours
parked, t, that would make the cost of each garage the same.

i. A = 4 + 3t 1

  B = 12 + 2t 2

ii. The hours required would be 8 hours.

Step-by-step explanation:

The charges at each of the garages can be expressed as;

i. For garage A,

A = 4 + 3t 1

ii. For garage B,

B = 12 + 2t 2

where A is the amount charged at garage A, B is the amount charged at garage B, and t is the number of hours.

To determine the number of hours  parked that would make the cost of each garage the same.

Let:

equation 1 = equation 2

4 + 3t = 12 + 2t

collect like terms

3t - 2t = 12 - 4

t = 8

The hours that would make the cost of each garage the same is 8 hours.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

you just switch the numbers basically so it would be 3/17