Really urgent Bus X, Bus Y and Bus Z leave the bus terminal every 35 minutes, 40 minutes and 42 minutes respectively. Given that the 3 buses leave the interchange together at 0620, what would be the next time the three buses leave together?

Step-by-step explanation:

Find the lowest common multiple between the numbers

35 = 5×7

40 = 2³×5

42 = 2×3×7

So the lowest common multiple is:

2³×3×5×7 =840 minutes

840 minutes is 14 hours so the next time they are all at the interchange is 2020 hours.

differentiate (x^14(x^-2)^4with respect to the variable

the parentheses don't balance in your input.

differentiate 0 with respect to

the final answer is

0

hope this