Y'all please answer this i really need an answer no need to give an explanation just tell me the answer pleasee Kenya is solving the equation LaTeX: 5\frac{3}{4}-\frac{1}{6}\:x=\:4\fra c{1}{2}5 3 4 − 1 6 x = 4 1 2. She gets to LaTeX: 1\frac{1}{4}=\frac{1}{6}x.\:1 1 4 = 1 6 x .Is this a valid way to solve the equation?

A) Yes, because she subtracts LaTeX: 4\frac{1}{2}4 1 2 from both sides and adds LaTeX: \frac{1}{6}x1 6 x to both sides.
B) Yes, because there are still fractions.
C)No, because you cannot change the side of the equations that LaTeX: xx is on.
D) No, because the coefficient on LaTeX: xx has changed from negative to positive.

7

step-by-step explanation:

the answer would be 7

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

step-by-step explanation:

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