(2+3i)+2i(2+3i) simplified

(2+3i)+2i(2+3i) = 1(2+3i) + 2i(2+3i) = (1+2i)(2+3i)

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.