PLEASE SOMEONE HELP MY SEMESTER IS ALMOST OVER A ball is thrown into the air with an initial upward velocity of 48 ft/s. It height "h" in feet after "t" seconds is given by the function "h(t)=-16t^2 + 48 + 4
1. What height will the ball be when 2 seconds have passed?
2. In how many seconds will the ball reach its maximum height?
3. What is the balls maximum height?

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

answer: c i think

step-by-step explanation:

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !