What are 2 ways i could solve 7-(4p+3)=-3(p+2)-(2p+3)

Simplifying

7 + -1(4p + 3) = -3(p + 2) + -1(2P + 3)

Reorder the terms:

7 + -1(3 + 4p) = -3(p + 2) + -1(2P + 3)

7 + (3 * -1 + 4p * -1) = -3(p + 2) + -1(2P + 3)

7 + (-3 + -4p) = -3(p + 2) + -1(2P + 3)

Combine like terms: 7 + -3 = 4

4 + -4p = -3(p + 2) + -1(2P + 3)

Reorder the terms:

4 + -4p = -3(2 + p) + -1(2P + 3)

4 + -4p = (2 * -3 + p * -3) + -1(2P + 3)

4 + -4p = (-6 + -3p) + -1(2P + 3)

Reorder the terms:

4 + -4p = -6 + -3p + -1(3 + 2P)

4 + -4p = -6 + -3p + (3 * -1 + 2P * -1)

4 + -4p = -6 + -3p + (-3 + -2P)

Reorder the terms:

4 + -4p = -6 + -3 + -2P + -3p

Combine like terms: -6 + -3 = -9

4 + -4p = -9 + -2P + -3p

Solving

4 + -4p = -9 + -2P + -3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '3p' to each side of the equation.

4 + -4p + 3p = -9 + -2P + -3p + 3p

Combine like terms: -4p + 3p = -1p

4 + -1p = -9 + -2P + -3p + 3p

Combine like terms: -3p + 3p = 0

4 + -1p = -9 + -2P + 0

4 + -1p = -9 + -2P

Add '-4' to each side of the equation.

4 + -4 + -1p = -9 + -4 + -2P

Combine like terms: 4 + -4 = 0

0 + -1p = -9 + -4 + -2P

-1p = -9 + -4 + -2P

Combine like terms: -9 + -4 = -13

-1p = -13 + -2P

Divide each side by '-1'.

p = 13 + 2P

Simplifying

p = 13 + 2P

Step-by-step explanation:

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a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.