What is the equation of the line that passes through point(-5,-3) and has a slope of -1

In this problem, we will be using the point-slope formula.

y - y₁ = m(x - x₁)

The point we are given, (-5, -3), represents (x₁, y₁) in the formula

and our slope which in this case is -1 represents our m.

Now let's plug all our information into the point-slope formula.

So we have y + 3 = -1(x + 5).

Remember that minus a negative means plus a positive

which is why I changed y - (-3) to y + 3 and the same for the x + 5.

So we have y + 3 = -1(x + 5).

Now distribute the -1 to get y + 3 = -x - 5

Now move the 3 to the right side by subtracting 3 to get y = -x - 8.

Now add x to both sides to get x + y = -8.

So the equation of this line in standard form is x + y = -8.

  q

step-by-step explanation:

each line from a vertex to the midpoint of the opposite side is called a median. the point where the medians intersect, point q, is the centroid.

the centroid of δabc is point q.

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