Help ASAP pls Parallelogram PQRS has diagonals PR and SQ that intersect at T. Given SP = 2a + 5, RQ = 5a - 1, ST = 3b- 3, and
SQ = 7b-9, what are the values of RQ and TQ?

A. RQ = 11, TQ = 3
B. RQ = 9, TQ = 1.5
C. RQ = 9, TQ = 6
D. RQ = 2, TQ = 6

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

you never say the total so we cant find the percentage used for petrol

step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47