1.Which postulate or theorem can you use to prove Triangle ABE = Triangle CDE? A SSS
B SAS
CASA
D AAS
B
с
D

AAS Postulate.

Step-by-step explanation:

The AAS Postulate states that if 2 angles and a non-included side are congruent on both triangles, then the two triangles are equivalent.

In this case, the first Angle is: ∠B ≅ ∠D (Given, both are 90° in measurement)

For the side: Line BE ≅ line DE (Given)

∡BEA ≅ ∡DEC (Definition of Vertical Angles)

AAS Postulate is therefore used.

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i'm not entirely sure

step-by-step explanation:

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