Mathematics, 22.01.2021 18:40, jakeyywashere

Dr. Silas studies a culture of bacteria under a microscope. The function b,(t) = 1200(1.8) ^t represents the number of bacteria t hours after Dr. Silas begins her study. ( Will Mark Brainliest please only leave an answer if you know how to solve. No Plagiarism Please.

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answered: aapowell1

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Dr. Silas studies a culture of bacteria under a microscope. The function b_1(t) = 1200(1.8)^t represents the number of bacteria t hours after she begins her study.

(a) What does the value of 1200 represent in this situation?

(b) What is the percent of growth or decay?

(d) The number of bacteria in a second study is modeled by the function . Will the bacteria present in both studies ever be equal for a certain value of t? Why or why not?

Function representing the number of bacteria after t hours is,

b_1(t)=1200(1.8)^t

a). Here 1200 is the initial population of the bacterial population.

b). We can rewrite the function as,

$b_1(t)=1200(1+\frac{80}{100} )^t$

Here. $\frac{80}{100}$ denotes 80% growth in the bacterial population.

c). For t = 5 hrs,

$b_1(t)=1200(1+\frac{80}{100} )^t$

$b_1(5)=1200(1+\frac{80}{100} )^5$

=1200(1.8)^5

≈ 22674 bacteria

d). Since, initial number of bacteria in both the studies are same and growing with the same rate.

Therefore, bacterial population will never be same at any point of moment.

answered: Guest

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

answered: Guest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

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step-by-step explanation:

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Dr. Silas studies a culture of bacteria under a microscope. The function b,(t) = 1200(1.8) ^t repres...