What is the equation of the line that passes through the points (-2,3) and (1,9)?

Solution given:

(x1,y1)=(-2,3)

(x2,y2)=(1,9)

we have

equation of line

(y-y1)=(x-x1)

(y-3)=(x+2)

y-3=2x+4

2x-y+4+3=0

2x-y+7=0;is a required equation.

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

1. 8

2. 9

3. 20

4. 3

5. 17

6. 2.2

7. 11.25

8. 1

9. 14

10. 2

step-by-step explanation:

thats the first half